# In a study of e-mail consultations with physicians at the University

Get college assignment help at uniessay writers In a study of e-mail consultations with physicians at the University of Virginia Children’s Medical Center, the monthly average was 37.6 requests with a standard deviation of 15.9 requests. (a)What is the probability of more than 50 requests in a given month? (b) Fewer than 29? (c) Between 40 and 50 requests? (d) What assumptions did you make? (Data are from S. M. Borowitz and J. Wyatt, “The Origin, Content, and Workload of E-Mail Consultations,” Journal of the American

## 1. Modeling clay comes in packages containing 12 canisters. The chance

1. Modeling clay comes in packages containing 12 canisters. The chance of getting a canister with red clay is 1/6. a. What is the probability that a randomly selected package of modeling clay contains at least one canister of red clay? b. How many canisters of red clay would you expect to find in each package? 2. The heights of 60 boys in the second grade at a local elementary school are normally distributed with a mean of 48 inches and a standard deviation of 6 inches. a. How many second grade boys would you expect to be between 40 and 54 inches tall? b. What is the probability that a randomly selected second grade boy is less than 42 inches?

## the maximum allowable value of each of the reactions is 180N.

the maximum allowable value of each of the reactions is 180N. neglecting the wieght of the beam detrmine the range of the distance d for which the beam is safe.

## A port CEO wants to study the proportion of ships arriving

A port CEO wants to study the proportion of ships arriving at his port on time. How many ships must be included in the sample if the CEO wants the error to be within 0.02 and a confidence level of 95% if: a. there is no information available that could be used as an estimate of the population proportion? b. a previous study suggests that 75% of ships arrive on time?

## please i need help with Methods of Point Estimation special in

please i need help with Methods of Point Estimation special in Method of Maximum Likelihood estimation i need examples with solution

## X is a random variable of size n, mean u, and

X is a random variable of size n, mean u, and variance c^2 and Y is a random variable with the same parameters from another sample. Let X* and Y* be the sample mean of each respective samples. Calculate P(|X*-Y*|<c/5)

## random sample of 70 voters found that 42% were going to

random sample of 70 voters found that 42% were going to vote for a certain candidate. Find the 99% confidence limit for the population proportion of voters who will vote for that candidate

## Please accept \$50.00 for this assignment. I do not have any

Please accept \$50.00 for this assignment. I do not have any more than the above price. I have couple more homeworks on the way. Thanx.

## Replacement times for T.V. sets are normally distributed with a mean

Replacement times for T.V. sets are normally distributed with a mean of 8.2 years and a standard deviation of 1.1 years (based on data from “Getting Things Fixed,” Consumers Reports). (a) Find the probability that a randomly selected T.V. will have a replacement time between 6.5 and 9.5 years. (b) Find the probability that a randomly selected T.V. will have a replacement time between 9.5 and 10.5 years.

## In a survey of 500 randomly selected high school students, it

In a survey of 500 randomly selected high school students, it was determined that 288 played organized sports. What is the probability that a randomly selected high school student plays organized sports?

## The Survey of Study Habits and Attitudes (SSHA) is a psychological

Get college assignment help at uniessay writers The Survey of Study Habits and Attitudes (SSHA) is a psychological test that measures the motivation, attitudes, and study habits of college students. Scores range from 0 to 200 and follow (approximately) a Normal distribution, with mean of 115 and standard deviation 25. A researcher suspects that incoming freshmen have a mean ?, which is different from 115, because they are often excited yet anxious about entering college. To verify her suspicion, she tests the hypotheses H0: ? = 115 Ha: ? 115. The researcher gives the SSHA to 100 incoming freshmen and observes a mean score of 119. Assume that the scores of all incoming freshmen are approximately Normal with the same standard deviation as the scores of all college students. If the researcher deems the data to be statistically significant, which of the following is true with respect to a conclusion reached? Choose one answer. a. The researcher has strong enough evidence to conclude that the average freshmen SSHA score differs from that of the average SSHA score for all college students. b. The researcher does not have strong enough evidence to conclude that the average freshmen SSHA score differs from that of the average SSHA score for all college students. c. The researcher has proven that the mean SSHA score for freshmen is, in fact, 115. d. The researcher has proven that the mean SSHA score for freshmen is not 115.

## 8-% of kids who visit a doctor have a fever, and

8-% of kids who visit a doctor have a fever, and 20% of kids with a fever have sore throats. What’s the probability that a kid who goes to the doctor has a fever and sore throat?

## I need to answers to this case study for moton picture

I need to answers to this case study for moton picture industry and the file contains all the data.

## HW#2: Decision Tree and EV Widget Manufacturing You must decide to

HW#2: Decision Tree and EV Widget Manufacturing You must decide to MANUFACTURE or NOT MANUFACTURE widgets. The uncertain variable is the future price of widgets. Your OPTIONS: 1. Manufacture widgets Future price, probability and present value of manufacturing widgets are as follows: Price = High Prob. = .7 Present Value = \$ 25,000 Price = Low Prob. = .3 Present Value = \$-15,000 2. Not manufacture widgets with Present Value = \$ 0 3. Hire a consultant: (at a cost of \$ 2,000) to predict if widget prices will be higher or lower. THEN, based on that prediction, (estimated to be 55% higher and 45% lower), determine to MANUFACTURE or NOT MANUFACTURE widgets: 3A. Manufacture widgets Future price, probability and present value of manufacturing widgets are as follows if the prediction is for higher prices: Price = High Prob. = .85 Present Value = \$ 25,000 Price = Low Prob. = .15 Present Value = \$-15,000 Future price, probability and present value of manufacturing widgets are as follows if the prediction is for lower prices: Price = High Prob. = .4 Present Value = \$ 25,000 Price = Low Prob. = .6 Present Value = \$-15,000 3B. Not manufacture widgets with Present Value = \$ 0 (a) Diagram the problem in the form of a decision tree. (b) Calculate which would be the better OPTION using Expected Value. Check answer: EV Manufacture = \$13,000 EV Hire Consultant = \$8,900

## The amounts of electricity bills for all households in a city

The amounts of electricity bills for all households in a city have a skewed probability distribution with a mean of \$139 and a standard deviation of \$30. Find the probability that the mean amount of electric bills for a random sample of 75 households selected from this city will be between \$132 and \$136. Round to 4 decimal places.

## a new battery’s voltage may be acceptable (A) or unacceptable(U). A

a new battery’s voltage may be acceptable (A) or unacceptable(U). A certain flashlight requires two batteries, so batteries will be independently selected and tested until two acceptable ones have been found. Suppose that 80% of all batteries have acceptable voltages, and let y denote the number of batteries that must be tested. What is p(2), that is, P(y=2)

## Let U and V be independent standard normal random variables and

Let U and V be independent standard normal random variables and X=U V, Y=U-2V. Find E[X|Y], cov(X,Y) and the joint probability density function of X and Y.

## The diameter of a brand of Ping-Pong balls is approximately normally

The diameter of a brand of Ping-Pong balls is approximately normally distributed, with a mean of 1.30 inches and standard deviation of 0.04 inch. If you select a random sample of 16 Ping-pong balls, a. what is the sampling distribution of the mean?

## tire will last 50000 miles before it comes bald or fails.

tire will last 50000 miles before it comes bald or fails. adjustment is made on any tire that doesn’t last 50000. purchase four tires. what is the probability all four tires will last at least 50000 miles

## I need help with developing a five-step hypothesis based on the

I need help with developing a five-step hypothesis based on the attached data set. Here is the beginning: The CIA conducted research on global demographics. Team C researched the CIA data set in order to formulate both a numerical and verbal hypothesis that will test two populations. In this paper, Team C will research the amount of exports against the amount of imports in certain countries identified in the data sets provided. This paper will contain the five-step hypothesis test on the data selected. This paper will also describe the results of the test and explain how the hypothesis testing can be used to answer our research question. The countries studied to determine the effectiveness to export and import are the United States, China, Canada and Chile. In the numerical hypothesis we came up with the mean of the two samples which was M1 (exports) =89.11 M2 (imports) = 89.43 From a sample size of 6 or n = 6. Our level of significance or alpha was .01. Our decision rule is to reject Ho if z calculated is > z critical. The null and alternate hypothesis is written as followed. Ho m1 greater than or equal to m2 H1 m1 > m2 Next we calculated the z and in order to make a decision. Because both samples are less than 30 we used the t distribution chart. The computed value of 6.05 is greater than the critical value of 1.05. Our decision is to reject the null hypothesis. The difference between the average amounts of exports going out of these countries is greater than the average amount of imports coming into these countries. So we conclude by saying that these countries make more profit off of exports than they do imports. The CIA conducted research on global demographics. Team C researched the CIA data set in order to formulate both a numerical and verbal hypothesis that will test two populations. In this paper, Team C will research the amount of exports against the amount of imports in certain countries identified in the data sets provided. This paper will contain the five-step hypothesis test on the data selected. This paper will also describe the results of the test and explain how the hypothesis testing can be used to answer our research question. The countries studied to determine the effectiveness to export and import are the United States, China, Canada and Chile. In the numerical hypothesis we came up with the mean of the two samples which was M1 (exports) =89.11 M2 (imports) = 89.43 From a sample size of 6 or n = 6. Our level of significance or alpha was .01. Our decision rule is to reject Ho if z calculated is > z critical. The null and alternate hypothesis is written as followed. Ho m1 greater than or equal to m2 H1 m1 > m2 Next we calculated the z and in order to make a decision. Because both samples are less than 30 we used the t distribution chart. The computed value of 6.05 is greater than the critical value of 1.05. Our decision is to reject the null hypothesis. The difference between the average amounts of exports going out of these countries is greater than the average amount of imports coming into these countries. So we conclude by saying that these countries make more profit off of exports than they do imports.

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